An individual has the following genotype Gene loci A and B a
Solution
(E) part ie.AB=7.5%;aB=42.5%
Explanation :-
nonrecombinant gametes would be A_______b, and a_______B and recombinant gametes (due to crossing over rearranging them) would be A_______B and a_______b
The recombination rate between these two genes is 15% - so recombinant gametes would be expected to be 7.5% each, which then leaves the nonrecombinant gametes with a probability of 42.5% each.
A testcross would be to cross this double heterozygote with an individual that is recessive for both traits.
AaBb x aabb
Offsring genotypes
A_______b a_______B A_______B a_______b
_________ _________ _________ _________
a b a b a b a b
42.5% 42.5% 7.5% 7.5%
