When the Celsius temperature is 0 degree the corresponding F
Solution
celsius 0 deg---- 32degF
celsius 100 deg ---- 212degF
slope , m =( 212-32)/ ( 100 - 0) = 180/100 = 1.8 degF/degC
F = mC +k = 1.8C +k , find k bu using one set of point ( 0, 32)
32 = 0 +k ---> k = 32
So,a) F = 1.8C +32
b) Rerranging F and C :
(F -32)/1.8 = C
c) for what temperature is F = C:
from part a) F = 1.8C +32
C = 1.8C +32---> - 0.2C = 32
C = - 160 deg
