Homework Soursethis is the 3rd time I post the question I need relative cum
this is the 3rd time I post the question I need relative cumulative frequency, and explain the K
Construct a grouped frequency table for the following set of exam scores (Put them in 6 equal length classes). Also, relative cumulative frequency.
60
90
76
81
59
40
48
61
57
78
86
65
63
54
68
93
71
78
79
67
75
87
76
74
86
57
62
95
80
70
K= Minimum = Maximum = Range= Length of classes=
I need a detailed solution, what is the K ??? how to get it? the relative cumulative frequency how get it?
no copy paste from another question
| 60 | 90 | 76 | 81 | 59 | 40 |
| 48 | 61 | 57 | 78 | 86 | 65 |
| 63 | 54 | 68 | 93 | 71 | 78 |
| 79 | 67 | 75 | 87 | 76 | 74 |
| 86 | 57 | 62 | 95 | 80 | 70 |
Solution
K stands for degrees of freedom
k = n-1 = 29
Minimum = 40
Maximum = 95
Range = 55
Total numbers = 30
Length of classes = 10.
Relative frequency is the ratio of frequency to total numbers as shown below in the table.
Frequency distribution table:
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