Find the particular solution of the differential equation dy
Find the particular solution of the differential equation dy/dx + y cos(x) = 2 cos (x) satisfying the initial condition y(0) = 4. Your answer should be a function of x.
Solution
This equation is separable.
Subtract the second terms from the left-hand side and factor out cos (x):
dy/dx = (2-y) cos(x), so
(1/(2-y)) dy = cos(x) dx.
Integrate:
ln(2-y) = -sin(x) + c1
Exponentiate (use e^(both sides)):
2 - y = e^(-sin(x) + c1)
2 - y = e^(-sin(x)) e^(c1)
2 - y = c2*e^(-sin(x)) (where c2=e^(c1))
y - 2 = -c2*e^(-sin(x))
y = 2 - c2*e^(-sin(x)) (general solution)
OK. Since y(0) = 4, substitute in x = 0, y = 4:
4 = 2 - c2*e^(-sin(0))
4 = 2 - (c2 * 1)
so c2 = -2, and the particular solution is
y = 2 + 2*e^(-sin(x)).
