Find a basis of the solution space S for each of the followi
Solution
Ans-
Again, B denotes a subset of a vector space V. Then, B is a basis if and only if any of the following equivalent conditions are met:
Every vector space has a basis. The proof of this requires the axiom of choice. All bases of a vector space have the same cardinality (number of elements), called the dimension of the vector space. This result is known as the dimension theorem, and requires the ultrafilter lemma, a strictly weaker form of the axiom of choice.
Also many vector sets can be attributed a standard basis which comprises both spanning and linearly independent vectors.
Standard bases for example:
In Rn, {e1, ..., en}, where ei is the ith column of the identity matrix.
In P2, where P2 is the set of all polynomials of degree at most 2, {1, x, x2} is the standard basis.
In M22, {M1,1, M1,2, M2,1, M2,2}, where M22 is the set of all 2×2 matrices. and Mm,n is the 2×2 matrix with a 1 in the m,n position and zeros everywhere else.
Change of basis
Main article: Change of basis
Given a vector space V over a field F and suppose that {v1, ..., vn} and {1, ..., n} are two bases for V. By definition, if is a vector in V then = x11 + ... + xnn for a unique choice of scalars x1, ..., xn in F called the coordinates of relative to the ordered basis {1, ..., n}. The vector x = (x1, ..., xn) in Fn is called the coordinate tuple of (relative to this basis). The unique linear map : Fn V with (vj) = j for j = 1, ..., n is called the coordinate isomorphism for V and the basis {1, ..., n}. Thus (x) = if and only if = x11 + ... + xnn.
A set of vectors can be represented by a matrix of which each column consists of the components of the corresponding vector of the set. As a basis is a set of vectors, a basis can be given by a matrix of this kind. The change of basis of any object of the space is related to this matrix. For example, coordinate tuples change with its inverse.
Examples
