A bracket is held in place by a pin joint A and slider joint
Solution
>> Problem 6
Rax = Reaction at Pin A in horizontal direction
Ray = Reaction at Pin A in vertical direction
Rb = Rection at B in Vertical Direction (because it is a slider joint)
>> Now, in Equilibrium,
Net Horizontal Force = 0
=> Rax = 85*cos35 = 69.628 N
and, in vertical Direction,
=> Ray + Rb = 85*sin35 = 48.754 N
>> Now, Moment about A = 0
=> 1*85*sin35 + 1.3*85*cos35 + 2*Rb = 0
=>Rb = - 69.635 N
So, Ray = 118.389 N
>> Reaction at B = 69.6 N ...Option C .....
>> Problem 7
>> Now, Let F1 = Resultant of Traingular distributed load
and, F2 = Resultant of Uniform Distributed Load
=> F1 = (1/2)*20*6 = 60 lb
and, it will act at (6 - 6/3) = 4 ft from A
>> F2 = 10*6 = 60 lb
and it will act at (6 + 6/2) = 9 ft ftom A
>> Now, Let Ra and Rb are the vertical reaction force at A & B respectively.
As, Ra + Rb = F1 + F2 = 120 lb ...(1)....
Taking Moment about A,
=> 4*60 + 9*60 = 12*Rb
=> Rb = 65 lb
From (1),
Ra = Vertical Reaction force at A = 55 lb ........OPTION E ........
