The block of mass m 5 kg travels from A to B on a flat surf

The block of mass m = 5 kg travels from A to B on a flat surface, from B to C on a cylindrical surface of radius R = 14 m, and at point C it separates from the surface becoming a projectile, finally hitting the ground at point D. All surfaces are smooth and the block has a velocity v_A = 6 m/s at point A.

The normal force applied by the surface on m just before it reaches B is ?

The normal force applied by the surface on m just after it passes B is ?

Solution

a) mg= 5*9.81=49.05 N

b) mg- mv²/r = 36.19N

Because mg - (force applied by surface) = m* (acceleration of body(which is equal to v²/r ))