The probability that a part produced by a certain factorys a
The probability that a part produced by a certain factory\'s assembly line will be defective is 0.013. Find the probabilities that in a run of 47 items, the following results are obtained. a. Exactly 3 defective items b. No more than 2 defective items c. At least 1 defective item
Solution
solution:
p(D)=0.013
p(nD)=1-0.013=0.987
a) for 3 defective items= C473(0.013)3(0.987)44
b) for not more than 2 defective iterms
possible cases
no items defective or 1 item defective or 2 items defective
hence probablity=C470(0.013)0(0.987)47 +C471(0.013)1(0.987)46+C472(0.013)2(0.987)45
c) probablity of atleast 1 item defective= 1-(prob of no items defective)
=1-C470(0.013)0(0.987)47
