The displacement of a hydraulic motor is V 125 mLr volumetri

The displacement of a hydraulic motor is V= 12.5 mL/r, volumetric efficiency v=90%, mechanical efficiency m=90%. If the output torque T=52.5 N m, and the rotation speed n=30 r/m, how much is the flowrate needed?

Solution

displacement D = 12.5 mL/r =12.5 * 10^-3 * 10^3 cm^3/rev = 12.5 cm^3/rev

volumetric efficiency = 90%

mechanical efficiency =90%

torque output =52.5N-m

rotational speed n =30rpm

flow rate = (displacement*n)/(1000*volumetric efficiency)

   =(12.5*30)/(1000*.9)

   =0.416 l/min