A study showed 120 eases of blue lung disease among 1000 ins
Solution
a)
Let p1 = proportion of those who use dry erase markers in class with blue lung disease
p2 = proportion of those who do not use dry erase markers in class with blue lung disease
Formulating the hypotheses
Ho: p1 - p2 <= 0
Ha: p1 - p2 > 0 [ANSWER]
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b)
Here, we see that pdo = 0 , the hypothesized population proportion difference.
Getting p1^ and p2^,
p1^ = x1/n1 = 0.12
p2 = x2/n2 = 0.09
Also, the standard error of the difference is
sd = sqrt[ p1 (1 - p1) / n1 + p2 (1 - p2) / n2] = 0.013693064
Thus,
z = [p1 - p2 - pdo]/sd = 2.19089023 [ANSWER]
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c)
Also, the p value is, as this is right tailed,
P = 0.014229868 [ANSWER]
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d)
As
P < 0.05, we Reject Ho. [ANSWER]
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e)
Thus, there is significant evidence that instructors who used dry erase markers in classes are more likely to develop \"blue lung disease\" than instructors who did not use dry erase markers in classes.

