3 OneSample Z Teacherstudent ratio 8 points Test of 18 vs 1

3.   One-Sample Z: Teacher/student ratio (8 points)

Test of = 18 vs 18

The assumed standard deviation = 0.76

Variable N Mean StDev SE Mean 95% CI Z P

Teacher/student ratio 16 18.875 6.087 0.190 (18.503, 19.247) 4.61 0.000

a.   State your decision and conclusion and explain how you reached your decision.

b.   Discuss what your confidence interval estimate means.

Solution

A.

As P = 0.000, then no doubt it is less than the significance level.

We reject the null hypothesis if p < significan level.

THUS, WE REJECT THE NULL HYPOTHESIS.

Thus, we conclude that THERE IS SIGNIFICANT EVIDENCE THAT THE TEACHER TO STUDENT RATIO IS NOT EQUAL TO 18.

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B.

The confidence interval estimate means that you are 95% confident that the true mean teacher/student ratio is between 18.503 to 19.247.