What is the relative risk of the event sum of two dices are

What is the relative risk of the event sum of two dices are greater than or equal to 10 with respect to the event at least one of the dices are 6?

Solution

see, cases where (sum>=10 and atleast 1 of them is 6) =(6,4),(6,5),(6,6),(4,6),(5,6)......

cases where (sum>=10 and none of them =6)= (5,5) ........

cases where (sum is not >=10 and one of them =6) = (6,1),(6,2),(6,3),(1,6),(2,6),(3,6).......

and for the case of rolling 2 dice together, total no. of cases =36...so, we can fill the last box by (36- 5 -1 - 6)=25.......

Relative risk=(5 /11) / (1 / 25 ) = 11.36