3x1260Solution3x1260 We would solve for value of x 3x12 6 Ta

(3x-1)^2+6=0??

Solution

(3x-1)^2+6=0

We would solve for value of x:

(3x-1)^2 =-6

Taking square root of both sides:

3x -2 = ( -6)^1/2

3x -2 = + /- i*sqrt(6)

3x = 2 + /- i*sqrt(6)

x = (2/3) + /- i*sqrt(6)/3

x = (2/3) + i*sqrt(6)/3 and   (2/3) - i*sqrt(6)/3

(3x-1)^2+6=0??Solution(3x-1)^2+6=0 We would solve for value of x: (3x-1)^2 =-6 Taking square root of both sides: 3x -2 = ( -6)^1/2 3x -2 = + /- i*sqrt(6) 3x = 2

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