Find the vertex focus and directrix of the parabola with equ

Find the vertex, focus, and directrix of the parabola with equation: x = 2y^2, and sketch its graph.

Solution

x=2y²

x=2(y-0)² + 0

This equation is of the form

x=a(y-k)²+h

Where vertex(h,k)=(0,0)

a=1/4p=2

p=1/8

focus=(h+p,k) = (1/8,0)

Directrix ,x=h-p

              x=-1/8