In C What is the output include using namespace std void fu

In C++, What is the output ?

#include <iostream>

using namespace std;

void fun2(int& a, int& b, int c, int& d)

{

        int temp;

        temp = a;

        a = b;

        b = c;

        c = d;

        d = temp;

}

void main()

{

        int a, b, c, d;

        a = b = c = d = 0;

        for(int i = 0; i < 2; i++){

               fun2(a, b, c, d);

               a += 4;

               b -= 3;

               c *= 2;

               d -= 1;

        }

        cout << a << \" \" << b << \" \" << c << \" \" << d << endl;

}

Solution

Answer :

#include <iostream>

using namespace std;

void fun2(int& a, int& b, int c, int& d)

{

     int temp;

     temp = a;

     a = b;

     b = c;

     c = d;

    d = temp;

}

void main()

{

        int a, b, c, d;

        a = b = c = d = 0;

        for(int i = 0; i < 2; i++){

               fun2(a, b, c, d);

               a += 4;

               b -= 3;

               c *= 2;

               d -= 1;

        }

        cout << a << \" \" << b << \" \" << c << \" \" << d << endl;

}

Answer :

1 -3 0 3

In C++, What is the output ? #include <iostream> using namespace std; void fun2(int& a, int& b, int c, int& d) { int temp; temp = a; a = b; b
In C++, What is the output ? #include <iostream> using namespace std; void fun2(int& a, int& b, int c, int& d) { int temp; temp = a; a = b; b

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