Solve logx230 log x Which of the following is an extraneous

Solve log(x2-30) = log x. Which of the following is an extraneous solution?

a) -6

b) -5

c) 5

d) 6

Solution

log(x^2 -30) = logx

equate the arguments on both sides:

x^2 -30 = x

x^2 -x -30 =0

x^2 -6x +5x -30 =0

x(x-6) +5(x-3) =0

(x+5)(x-3) =0

x=-5 ; x=3

Now x=-5 is not a solution as domian of logx is x>0

so, x= 3 is the only solution

x= -5 is the extraneous solution

Option B

Solve log(x2-30) = log x. Which of the following is an extraneous solution? a) -6 b) -5 c) 5 d) 6Solutionlog(x^2 -30) = logx equate the arguments on both sides:

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