For the fournode quadrilateral element a shown in the global
Solution
given the 4 node rectangle with coordinates (4,-3), (4,3), (-4,3),(-4,-3) we need to map to the quadrilateral
(4,3), (0,3),(-4,-3),(0,-3)
Writing the cooridnates for x and y as a matrix
[4 4 -4 -4] row 1 ( x\'s)
[-3 3 3 -3] row 2 (y\'s)
should transform to [4 0 -4 0]
[3 3 -3 -3]
The matrix that does this is the Jacobian, and by solving it is {1/2 -2/3}
{3/4 0}
The determinant is (1/2)* 0 - (-2/3)*3/4 = 1/2
the area of the rectanglke is 48, that of the quadrilateral is 24, the mapping reduces the area by 1/2 which is what is shown by the determinant.
Mapping (.6,.6) thru the Jacobian, get [(1/2)*.6 -2/3*.6], [ 3/4*.6, 0] = -0.1,0
Acceptable error in FEM, depends on the mapping and the distortion measured by Jacobians.
Accpetable is 5-10%
![For the four-node quadrilateral element (a), shown in the global coordinate system, evaluate [J] (the Jacobian), and |J| (its determinant). For element (b), de For the four-node quadrilateral element (a), shown in the global coordinate system, evaluate [J] (the Jacobian), and |J| (its determinant). For element (b), de](/WebImages/12/for-the-fournode-quadrilateral-element-a-shown-in-the-global-1012615-1761522867-0.webp)