solve for x tsecsquareroot2agsinxcosx a10ft g32ftsec2 t12 se

solve for x. tsec=(squareroot(2a/(gsinxcosx)) a=10ft, g=32ft/sec^2 t=1.2 sec

sect = (squareroot( 2a/(gsinxcosx) )

a= 10ft ; g = 32 ft/sec^2 sec^2t = 1.2 sec

sect = (squareroot( 2a/(gsinxcosx) )

Squaring both sides:

sec^2t = 2a/g(sinxcosx)

Plugging all values:

1.2 = 2*10/( 32(sinxcosx) )

32sinxcosx = 20/1.2

sinxcosx = 20/1.2*32 = 0.52

2sincosx = 1.04

Approximately : 2sinxcosx = 1

sin2x = 1

x = (1/2)sin^-1(1)

x = pi/4