A 030 kg object is attached to a spring with force constant

A 0.30 kg object is attached to a spring with force constant 151 N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the spring is compressed 0.11 m.

(a) Find the force on the object.
1 N
(b) Find its acceleration at that instant
2 m/s²

Solution

spring force = kx

where k = spring constant, x = compression or stretch

a) force = kx = 151 * 0.11 = 16.61 N

b) Fnet = ma

a = F/m = 16.61 / 0.30 = 55.37 m/s^2