x 20 y 20 y 20 ns for a church fundraising bazaar 49 She nee

x 20 y 20 y 20 ns for a church fund-raising bazaar. 49) She needs 8 hours to make a hat and 3 hours to make an afghan and she has 24 hours available. Write an inequality that describes situation and use the inequality to decide of whether s can make 2 hats and 2 afghans the number in the time allowed. Letxrepresent the hats and y the number of afghans that she makes. B) 8x 3y 24, yes A) 8x 3y 24; no D) 8 3y s 24; yes C) 8x 3y s 24; no

Solution

If x is the numbers of hats and y is the number of afghans made by the volunteer, then the time taken to make x number of hats is 8x ( as making of 1 hat takes 8 hours) and the time taken to make y number of afghans is 3y houra ( as making of 1 afghan takes 3 hours). Since the volunteer has 24 hours\' time, we have 8x + 3y 24. Thus the answer D is correct. Now, if we substitute x = 2 and y = 2 in the inequality 8x + 3y 24, we have 8 * 2 + 3 * 2 24 or, 16 + 6 24 or, 22 24 which is correct. Thus the volunteer can make 2 hats and 2 afghans in the time allowed i.e. 24 hours.