h4lp with stats homeworkSolutiona A TTT HTT THT TTH option

Solution

a)

A = {TTT, HTT, THT, TTH} [option C]

B = {HTT, THT, TTH, HHH} [option C]

A U B = {TTT, HTT, THT, TTH, HHH} [OPTION A]

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Ac = {HHH, HHT, HTH, THH} [option c]

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A n B = {HTT, THT, TTH} [answer, option A]

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b)

There are 8 possibilities in tossing 3 coins. Hence, we just divide the number of elements in each set by 8 to get the probabilities:

P(A) = 1/2
P(B) = 1/2
P(A U B) = 5/8
P(Ac) = 1/2
F(A n B) = 3/8

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c)

P(A U B) = P(A) + P(B) - P(A n B) = 1/2 + 1/2 - 3/8 = 5/8 [answer]

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OPTION B: The same result.

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d)

OPTION C: No, events A and B are not mutually exclusive becasue P(A n B) =/= 0.