Please answer these questions a Complete the reaction equati

Please answer these questions:

(a) Complete the reaction equation for electron capture by 7Be. Use azk N notation for isotopes. Use the symbols alpha for , beta-for -, beta+ for +, gamma for Y, nue for ve, antinue for Ve, e+ for e+, e-for e, n for a neutron and p for a proton, as required. 7 7 4 Be 3 Li 4 (b) Calculate the energy released MeV

Solution

(a). mass of 7 Be is m = 7.01692983u

Mass of electron m \' = 0.000548579909 u

Mass of 7 Li is M = 7.01600455 u

Mass of neutron M \' = 1.008665 u

mass defect dm = (m+ m\') -(M+M\')

                         = -1.00719114 u

We know 1 u = 931.5 MeV

So,energy released E = dm x 931.5 MeV

                                = 938.19 MeV

(b).mass of 239 Pu is m = 239.052 1634 u

mass of neutron m \' = 1.008665 u

mass of 92 kr is M = 91.926153 u

mass of 144 Ce is M \' = 143.913643 u

mass defect dm = m+m \' -M-M\' -4m\'

                        = m-M-M\' -3m\'

                        = 0.1863724 u

Energy released E = dm x 931.5 meV

                            = 173.6 MeV