A charge is moving perpendicular to a magnetic field and exp

A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 2.06 × 10-3 N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were 44.6o, what would be the magnitude of the magnetic force that the charge would experience?

Solution

F = q (v × B)

|F| = q |v| |B| sin theta

f = F * sin theta

= 2.06 * 10^-3 * sin 44.6

= 1.45 * 10^-3 N