06 Im 04 05 0 05 02 0 0 0 02 10 15 1 05 0 05 1 Figure 1 Left

0.6 Im 0.4 0.5 0 -0.5 0.2 0 0 0 -0.2 10 15 1 -0.5 0 0.5 1 Figure 1: (Left) Impulse response and (right) pole-zero plot of an FIR filter

Solution

Impulse responce:

clear all;

close all;

clc;

t=-2:1:2;

y=[0 0 1 0 0];

stem(t,y);

xlabel(\'time\');

ylabel(\'amplitude\');

title(\'impulse sequence\');

second method:

clear all;

close all;

clc;

x1=input(\'enter the first sequence\');

x2=fliplr(x1);

l=length(x1);

x1=fft(x1);

x2=fft(x2);

f=x1.*x2;

j=ifft(f);

subplot(2,2,1);

stem(x1);

xlabel(\'input sequence\');

ylabel(\'amplitude\');

title(\'input sequence\');

subplot(2,2,2);

stem(j);

xlabel(\'time\');

ylabel(\'amplitude\');

title(\'impulse responce\')