m DBC 90 and m


m < DBC= 90, and m <2=28. Find m <1

m ORC 50, end m 2 28 Find m. 1

Solution

Solution:

Given m < DBC = 90, and m < 2 = 28

Now we have to find m <1

We know that a triangle with 3 angles will add upto 180 degrees.

Assume m <1 = x

m < DBC + m <2 + m<1 = 1800

90 + 28 + x = 1800

118 + x =1800

x = 180-118

x = 620

x = 620

Hence m<1 = 620

 m < DBC= 90, and m <2=28. Find m <1 m ORC 50, end m 2 28 Find m. 1 SolutionSolution: Given m < DBC = 90, and m < 2 = 28 Now we have to find m &l

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