Find the compressibility factor of a superheated H2O vapor a
Find the compressibility factor of a superheated H_2O vapor at 150 bar and 500 degree C using the following two methods: (a) the definition of compressibility: Z = pv/RT; and (b) the Nelson-Obert chart in Figure A-15. Please justify if H_2O under given conditions can be considered as ideal gas based on the compressibility factor calculated. The critical pressure, critical temperature, and gas constant R of water can be found in Table A-l. Please find the specific volume of a pure O_2 at 200 K and 2.0 MPa by the two methods: Employ the ideal gas equation. Use the compressibility chart if the critical point for O_2 is known: T_cr = 154.6K, p_cr = 5.05 MPa.
Solution
6.a) From steam table A-6 superheated vapour Yunus Cengel and Boles
at T= 500oC and P= 150 bar
v = 0.020828 m3/kg
Z = (Pv) / (RT) = (150 X 105 X0.020828) / ((8.314 / 18.02) X 773) = 0.875
Hence compressibility factor Z = 0.875
6.b) From Table A-1 Yunus Cengel and Boles
Crital Pressure (Pc) of Water = 220.6 bar
Critical Temperature of Water (Tc) = 647.1 K
Hence,
Reduced Pressure (Pr) = P/Pc = 150 / 220.6 = 0.679
Reduced Temperature (Tr) = T/Tc = (500+273) / 647.1 = 1.19
Hence from Nelson - Obert generalized compressibility chart
Z = 0.86
