Im lost A researcher wishes to estimate with 95 confidence t
Solution
a)
Note that
n = z(alpha/2)^2 p (1 - p) / E^2
where
alpha/2 = 0.025
As there is no previous estimate for p, we set p = 0.5.
Using a table/technology,
z(alpha/2) = 1.959963985
Also,
E = 0.01
p = 0.5
Thus,
n = 9603.647052
Rounding up,
n = 9604 [answer]
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b)
Note that
n = z(alpha/2)^2 p (1 - p) / E^2
where
alpha/2 = 0.025
Using a table/technology,
z(alpha/2) = 1.959963985
Also,
E = 0.01
p = 0.34
Thus,
n = 8620.233594
Rounding up,
n = 8621 [answer]
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c)
OPTION B: Having an estimate of the population proportion REDUCES the minimum sample size required.

