A circuit is constructed with a resistor two inductors one c
A circuit is constructed with a resistor, two inductors, one capacitor, one battery and a switch as shown. The value of the resistance is R1 = 267 . The values for the inductances are: L1 = 360 mH and L2 = 149 mH. The capacitance is C = 75 F and the battery voltage is V = 12 V. The positive terminal of the battery is indicated with a + sign.
1)
The switch has been closed for a long time when at time t = 0, the switch is opened. What is UL1(0), the magnitude of the energy stored in inductor L1 just after the switch is opened?
J
2)
What is o, the resonant frequency of the circuit just after the switch is opened?
radians/s
3)
What is Qmax, the magnitude of the maximum charge on the capacitor after the switch is opened?
C
4)
What is Q(t1), the charge on the capacitor at time t = t1 = 2.66 ms. Q(t1) is defined to be positive if V(a) – V(b) is positive.
C
5)
What is t2, the first time after the switch is opened that the energy stored in the capacitor is a maximum?
ms
6)
What is the total energy stored in the inductors plus the capacitor at time t = t2?
J
Solution
1) UL1 = 1/2 L1 I2
I = V / R1 = 12 / 267 = 0.0449 A
UL1 = 1/2 L1 I2 = 1/2 (360 * 10-3) * 0.04492
= 0.000363 J
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2) w = 1 / sqrt[LC] = 1 / sqrt[(L1 + L2) C]
= 1 / sqrt[((360 * 10-3) + (149 * 10-3)) 75 * 10-6]
= 161.85 rad/s
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3) Q2max / 2 C = 1/2 I2 (L1 + L2)
Qmax = sqrt [C I2 (L1 + L2)]
= sqrt [75 * 10-6 * 0.04492 ((360 * 10-3) + (149 * 10-3))]
= 2.77 * 10-4 C
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4) Q(t) = Qmax cos(wt + phi/2 )
= 2.77 * 10-4 * cos(161.85 * 2.66 * 10-3 + pi/2 )
= 2.76 * 10-4 C

