Consider Fig 2 showing the side and front views of a vertica

Consider Fig. 2, showing the side and front views of a vertical right-angled triangular surface ABC, with vertex at the free surface of a liquid (water). Knowing that h = 3m, determine: (a) the hydrostatic force F acting on the surface ABC; (b) the moment about BC of the force F (c) If the surface would be circular instead of triangular (with diameter D-3m, and still just touching the free surface at its top), what would then be the value of the hydrostatic force? (d) In the case of the triangular surface, would the center of pressure be located immediately below the centroid of the surface? Answer with Yes or No, and give a short justification for your answer. unit gravity force = Fig. 2

Solution

1)F= rho ×g×h= 1000k9.81×3=29430KN

2)Moment=M= F×(h÷3)=29430×3÷3=29430KNm

3)F=rho×g×D= 1000×9.81×3=29430KN

4)YES, because force is applied at the h/3from the bottom