If I use partial fractions and set up the problem as AxBx4Cx

If I use partial fractions, and set up the problem as: (A/x)+(B/(x-4))+(C/(x+4)), I find C has a value of zero, B=1/4 and A=-1/4. Integrating, I find -1/4ln|x|+1/4ln|x-4|+C. This seems right to me, but Wolfram Alpha says the answer is quite different. Am I missing something? Also, I\'m unsure if the coefficient zero for C means that the integral of C/x+4=0.

Clarification would be great, thanks.

the value are wrong

A = -1/16

B = 1/32

C = 1/32

$If I use partial fractions, and set up the problem as: (A/x)+(B/(x-4))+(C/(x+4)), I find C has a value of zero, B=1/4 and A=-1/4. Integrating, I find -1/4ln|x|+$

If I use partial fractions and set up the problem as AxBx4Cx

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