Write the slopeintercept form of the equation of the line th

Write the slope-intercept form of the equation of the line through the given point perpendicular the given line. point: (-7, -8) line: -9x -45y = 9

Sol:

line perpendicular to a given line ax + by + c = 0 is bx - ay + = 0, where is a constant.

here ax + by + c = 0 is -9x+(-45)y-9=0

a=-9 b=-45

so bx - ay + =0

-45x-(-9)y+ =0

-45x+9y+ =0

given this line passes through(-7,-8)

put x=-7 and y=-8 to get k

-45(-7)+9(-8)+ =0

315-72+ =0

=-243

the requuired line is

-45x+9y-243=0

slope yintercept form of this line is y=mx+c

9y=45x+243

y=(45/9)x+(243)/9

y =5x+27

is the required slope intercept form of line

slope=m=5

y intercept=c=27