If csc x squareroot13 and cos x 0 find sin2x Solutioncscx

If csc x = -squareroot13 and cos x > 0, find sin(2x).

cscx =-13

write cscx as 1/sinx

1/sinx =-13

sinx =-1/13

opposite side =1 ,hypotenuse =13

opposite side² +adjacent side² =hypotenuse²

1² +adjacent side² =(13)²

adjacent side =12

cosx =adjacentside/hypotenuse

cosx =12/13

sin(2x)

=2sinx cosx

=2(-1/13)(12/13)

=-(212)/13

sin(2x)=-(212)/13