write the answer on paper plz A car sales manager records th

A car sales manager records that in June 25 cars were sold with an average price of dollar 16, 500 and a standard deviation of dollar 2, 000. In December 20 cars were sold with an average price of dollar 17, 300 and a standard deviation of dollar 1,600. The two populations are normally distributed. Is there significant evidence suggest that the average price of cars in June is less than the average price of cars in December? Test at the 5 percentage significance level.

Solution

Set Up Hypothesis
Null, Ho: u1 >= u2
Alternate , H1: u1 < u2
Test Statistic
X(Mean)=16500
Standard Deviation(s.d1)=2000
Number(n1)=25
Y(Mean)=17300
Standard Deviation(s.d2)=1600
Number(n2)=20
we use Test Statistic (Z) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
Zo=16500-17300/Sqrt((4000000/25)+(2560000/20))
Zo =-1.49
| Zo | =1.49
Critical Value
The Value of |Z | at LOS 0.05% is 1.645
We got |Zo | =1.491 & | Z | =1.645
Make Decision
Hence Value of | Zo | < | Z | and Here we Do not Reject Ho
P-Value: Left Tail - Ha : ( P < -1.49 ) = 0.06802
Hence Value of P0.05 < 0.06802,Here We Do not Reject Ho

[ANSWER] The average price of cars in june is n\'t less than the
average price of cars in december