One lbmol of an nonideal gas initially at 630R and 4 atm Sta

One lb-mol of an non-ideal gas, initially at 630R and 4 atm (State 1) is changed to 980 R and 12 atm (State 3) by the processes of constant volume heating to 12 atm followed by isobaric cooling to 980R. State 2 is at the end of the constant volume heating. You will need to find T2! Assume the gas has constant heat capacities of Cp = 7 Btu/lb-mole R and Cv = 5 Btu/lbmole R and that the gas constant can be taken as R = 2 Btu/lb-mole R. The critical properties are Tc = 700 R and Pc = 10 atm and the acentric factor is omega = 0.336. Calculate T2, Q, W, U, H, and S for the process in English units.   

(a) Assuming ideal gas behavior.

(b) Use the generalized corresponding states theory to correct the results in part (a) using the Lee/Kesler Tables in Appendix C. Note that T2 will now differ from the result in part (a).   
HINT: To find T2 use ZRT PV to compare values of r ZT at States 1 and 2. You will need to guess a value of 2 rT and use the Tables to calculate 2 Z and compare to the values at State 1.   

Solution

One lb-mol of an non-ideal gas, initially at 630R and 4 atm (State 1) is changed to 980 R and 12 atm (State 3) by the processes of constant volume heating to 12 atm