Individuals with the indicated genotypes were crossed All ge

Individuals with the indicated genotypes were crossed. All genes assort independently. Aa Bb CC Dd ee x aa Bb cc Dd Ee What fraction of the progeny will have the following phenotypes? (show your calculations) A B C D E abcde Abed E How many different phenotypic combinations may be observed among the progeny of this cross? How many different genotypic combination may occur among the progeny of this cross Consider the following pedigree that shows the inheritance of a rare genetic disease. All affected individuals are indicated.

Solution

Answer:

5).

AaBbCCDdee X aaBbccDdEe-----Parents

Aa X aa = Aa (1/2), aa (1/2)

Bb X Bb = BB (1/4), Bb (1/2), bb (1/4) or B_ 3/4 & bb= 1/4

CC X cc = Cc (1)

Dd X Dd = DD (1/4), Dd (1/2), dd (1/4) or D_ 3/4 & dd= 1/4

ee X Ee= Ee(1/2), ee(1/2)

A).ABCDE= A_B_C_D_E_ = 1/2* 3/4* 1* 3/4 *1/2 = 9/64

B).abcde = aabbccddee= 1/2*1/4*0*1/4*1/2 = 0

C). AbcdE= A_bbccddE_ = 1/2* 1/4* 0* 1/4* ½= 0

D). 16 phenotypes

A phenotypes= 2

B phenotypes= 2

C phenotypes = 1

D phenotypes= 2

E phenotypes= 2

2 * 2 * 1 * 2 * 2 = 16 phenotypes

E). 36 genotypes

A genotypes = 2

B genotypes =3

C genotypes =1

D genotypes =3

E genotypes = 2

2 * 3 * 1 * 3 * 2 = 36 genotypes