Analyze the circuit below using an ideal diode voltage sour

Analyze the circuit below using an ideal diode + voltage source model, where V_f = 0.7V. Consider all statements below and select all that are correct. If V_1 is a ramp, V_1 = 2t volts where t is in seconds, and = 0V, then the diode first turns on at t = 0.7sec. If V_1 = 0.5V and V_2 = 0V, then the diode is ON. If V_1 = 10V and V_2 = 9V, then the diode is OFF. If V_1 = 4V and V_2 = 2V, then the diode is ON. If V_1 is a ramp, V_1 = t volts where t corresponds to time, and V_2 = 0V, then the diode first turns on at t = 0.1 sec. If V_1 = 2V and V_2 = 2V, then the diode is OFF.

Solution

Diode will turn on when (V1-V2) >= Vf

(1)For ramp input V1= 2t , and V2=0,

Diode will first turn on at t= Vf/2= 0.3s

Hence false.

(2) V1= 0.5 is less than Vf, so diode is off

(3) as (V1-V2)=1>Vf, hence diode is ON

(4) (V1-V2)=2>VC, hence diode is ON

(5) v1= t, then at t=0.7 s, diode is ON

(6) v1-v2=0<Vf, hence diode is OFF