Solve the equation for solutions over the interval 0 degree

Solve the equation for solutions over the interval [0 degree, 360 degree) 6cos^2 theta sin theta + 3cos^2 theta = 0 Select the correct choice below and if necessary fill in the answer box to complete your The solution set is {squarebox} (Type your answer in degrees Do not include the degree symbol in your answer Rout decimal place as needed Use a comma to separate answers as needed) The solution is the empty set

Solution

6cos²theta sin theta + 3 cos²theta=0

3cos²theta(2sin theta+1)=0

cos²theta=0     and sin theta=-1/2

cos theta=0     and sin theta=-1/2

theta=cos^-10    and theta =sin^-11/2

theta=0,3pi/2,      and theta=pi/6, 5pi/6

theta=0,pi/6, 5pi/6,3pi/2