The same coop student calculates the area of lot 2 shown in

The same coop student calculates the area of lot 2 shown in Fig. P3.5 as 50,000 m^2. Is this the correct answer? If not, find the correct answer. Dimension of lot 2 in the new subdivision.

Solution

area of lot 2 = area of rectangle - area of triangle

area of rectangle = 200m * 300m = 60000m^2

for area of triangle use formula 1/2 * base * height

calculating height from tan formula

applying tan formula on the triangle whose angle is (120 - 90) = 30 degrees

tan 30 = height / base

base = 200 m

height = tan 30 * 200 = 115.47 m

therefore, area of triangle = 1/2 * 200 * 115.47 = 11547.005 sq m

so, area of lot 2 = 60000 - 11547.005 = 48453 m^2

 The same coop student calculates the area of lot 2 shown in Fig. P3.5 as 50,000 m^2. Is this the correct answer? If not, find the correct answer. Dimension of

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