What are the asymptotes of the function fx x2 x 62x2 2So
What are the asymptotes of the function f(x) = x^2 + x - 6/2x^2 - 2?
Solution
lets first calculate the vertical asymptotes as
so we shall set denominator equal to zero and solve
2x2-2 = 0
x2= 2/2
x2=1
x = +-1 , the 2 vertical asymptotes are +-1
now to find the horizontal aymptotes , we see the degree of numerator or denominator are equal , so we take the ratio of the highest degree terms of numnerator and denominator
x2/2x2 = 1/2 , which would be our horizontal asymptote
