Find the five remaining trigonometic functions of theta sec

Find the five remaining trigonometic functions of

theta.

sec (theta) = 6/5, sin theta < 0

sin =?

cos=?

Tan=?

Csc=?

Cot=?

Sec=6/5

sec theta=6/5

cos theta=1/sec theta=5/6

Here adjacent=5 and hypotenuse=6

Therefore opposite=sqrt(6^2 - 5^2)=sqrt11

and sin theta is negative

sin theta=opposite/hypotenuse=- sqrt11/6

csc theta= 1/sin theta= -6/sqrt11= -6sqrt11/11

tan theta=sin theta/cos theta= -sqrt11/5

cot theta=1/tan theta= -5/sqrt11=-5sqrt11/11