Consider a twofactor factorial design with three levels in f

Consider a two-factor factorial design with three levels in factor A. three levels in factor B, and four replicates in cad, of the nine cells, That is. there are two degrees of freedom in determining the factor A variation, two degrees of freedom in determining the factor B variation, four degrees of freedom in determining the interaction variation, and 27 degrees of freedom in determining the random variation. Assume that SSA= 110, SSB = 130, SSE = 405, and SST=685. Answer parts (a) through (d). a. What is SSAB? SSAB=

Solution

df of factor A variation is 2

df of factor B variation is 2

df of interaction of A and B is 4

df of random variation is 27

Given, SSA = 110, SSB = 130, SSE = 405, SST = 685

Therefore, SSAB = SST - (SSA+SSB+SSE) = 40