State the null and alternative hypotheses Choose the statist

State the null and alternative hypotheses.

Choose the statistical test.

Select the desired level of significance.

Calculate the value of the test statistic.

Show all your work for calculations that must be done \"by hand\".

For SPSS-generated results, show the relevant output tables.

Determine the critical value for the test statistic.

Interpret the results.

Calculate the effect size, if applicable.
calculate the power

Write your interpretation in the APA format

Question 1

Plant therapists believe that plants can reduce the stress levels of humans. A Kansas State University study was conducted to investigate this phenomenon. Two weeks prior to final exams, 10 undergraduate students took part in an experiment to determine what effect the presence of a live plant, a photo of a plant, or absence of a plant has on the student\'s ability to relax while isolated in a dimly lit room. Each student participated in three sessions- one with a live plant, one with a plant photo and one with no plant (the control). During each session, finger temperature was measured at one-minute intervals for 20 minutes. Since increasing finger temperature indicates an increased level of relaxation, the maximum temperature (in degrees) was used as the response variable. What can you conclude using an of .05?

Student

Live Plant

Plant Photo

No Plant

1

97.6

93.5

91.4

2

98.5

96.6

90.9

3

95.4

95.8

94.8

4

96.7

96.2

93.7

5

95.5

96.6

94.0

6

96.8

95.5

96.7

7

95.7

94.6

95.2

8

96.2

97.2

93.0

9

96.0

94.8

94.6

10

96.6

92.6

95.6

Student	Live Plant	Plant Photo	No Plant
1	97.6	93.5	91.4
2	98.5	96.6	90.9
3	95.4	95.8	94.8
4	96.7	96.2	93.7
5	95.5	96.6	94.0
6	96.8	95.5	96.7
7	95.7	94.6	95.2
8	96.2	97.2	93.0
9	96.0	94.8	94.6
10	96.6	92.6	95.6

Solution

The null hypothesis is that the means are all equal where as the alternative hypothesis is that at least one of
the means is different.

The test statistic is the ratio of group and error mean squares is F-statistic

The level of significance is 0.05

Anova: Single Factor

SUMMARY

Groups Count Sum Average Variance

Column1 10 965 96.5 0.948889

Column2 10 953.4 95.34 2.149333

Column 3 10 939.9 93.99 3.305444

ANOVA

Source of Variation SS df MS F P-value F crit

Between Groups 31.56067 2 15.78033 7.392796 0.002751 3.354131

Within Groups 57.633 27 2.134556

Total 89.19367 29