Thermodynamics Question 16 Follow Link Below for question pl

Thermodynamics

Question 16: Follow Link Below for question please.

http://imgur.com/QxIpWRX

Solution

a)

For Water R=0.4615 KJ/Kg-K

From Ideal Gas equation

PV=RT

So Pressure of the steam

P=RT/V =0.4615*(400+273.2)/0.02

P=15534 kPa

b)

From Generalized compressibility chart

P=12574 kPa

c)

From Steam tables

P =12576 kPa