A springmass system consisting of several masses and a sprin
Solution
We know that the time period of motion for a spring mass system is given as T = 2(m/k)
Squaring the above relation, we get: T2 = 42m/k which is the form given in the question.
Clearly, if we plot T2 against m, we will get a straight line with slope equal to 42/k [Compare it with the form y = Bx where B is the slope of the line]
Part 3.) Now from the graph we can find the slope of the given line which would be same as the value for B.
Hence B = (0.8 - 0.4) / (0.2 - 0.1) = 4 is the required value.
Part 4.) Now, from the fitted equation we can say that B is same as 42/k. Also, we know that value for B from the graph, hence we can equate the above two and then resolve to find the required value for K.
Part 5.) Equating B with 42/k,. we get:
42/k = 4
or. k = 2
or, k = 9.8596 N /m
Therefore the required spring constant is 9.8596 N /m
