An ultracentrifuge accelerates from rest to 99500 rpm in 18

An ultracentrifuge accelerates from rest to 99.500 rpm in 1.8 min. Randomized Variables f = 99.500 rpm t = 1.8 min l = 9.3 cm What is its angular acceleration in rad/s^2? Numeric: A numeric value is expected and not an expression. a = What is the tangential acceleration of a point 9.3 cm from the axis of rotation in m/s^2? Numeric: A numeric value is expected and not an expression. a_t = What is the centripetal acceleration in multiples of g of this point at full speed? Numeric: A numeric value is expected and not an expression. a/g =

Solution

= 99500rev/min * 2rad/rev * 1min/60s = 10 438 rad/s

t = 1.8 min = 108 Seconds

a) = o + at
10438 rad/s = 0rad/s + *108s
= 96.65 rad/s²

b)  a_t = r = 96.65rad/s² * 0.093m = 8.99 m/s²

(c) a_r = ²r = (10438rad/s)² * 0.093m/9.8 = 1.034e6 \"g\"

 An ultracentrifuge accelerates from rest to 99.500 rpm in 1.8 min. Randomized Variables f = 99.500 rpm t = 1.8 min l = 9.3 cm What is its angular acceleration

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