Can a population with more than 80 heterozygotes for a locus
Can a population with more than 80% heterozygotes for a locus be in Hardy- Weinberg equilibrium? Less than 10%? Explain why WITH MATH
Can a population with more than 80% heterozygotes for a locus be in Hardy- Weinberg equilibrium? Less than 10%? Explain why WITH MATH
Solution
A population with more than 80% or less than 10% heterozygotes for a locus cannot be in Hardy- Weinberg equilibrium. Because during recombination, the alleles are distributed, so that the heterozygotes percent will never be more than 80% or less than 10%.
