72 a Word number 835o in the memory shown in Figure 72 conta

7-2. (a) Word number (835)o in the memory shown in Figure 7-2 contains the 72· (a) Word number (835)10 in the memory shown in Figure 7-2 contains the binary equivalent of (15,103)1o- List the 10-bit address and the 16-bit memory contents of the word. (b) Repeat part (a) for word number (513)o containing the binary equivalent 10.

Solution

We just need to change decimal values to binary values

a)       Word number (835)₁₀ when written to 10-bit address is = 1101000011

Memory content (15,103)₁₀ when changed to 16-bit is = 0011101011111111

b)       Word number (513)₁₀ when written to 10-bit address is = 1000000001

Memory content (44,252)₁₀ when changed to 16-bit is    = 1010110011011100