Four consecutive odd integers have the sum of 64 Which are t

Four consecutive odd integers have the sum of 64. Which are the integers .

Solution

We\'ll write the first odd integer as x.

The second consecutive odd integer is x + 2.

The third consecutive odd integer is x + 4.

The fourth consecutive odd integer is x + 6.

The sum of the integers is 64:

x + (x+2) + (x+4) + (x+6) = 64

Now, we\'ll remove the brackets and we\'ll combine like terms:

4x + 12 = 64

We\'ll subtract 12 both sides:

4x = 64 - 12

4x = 52

We\'ll divide by 4:

x = 13

The first odd integer is x = 13.

The second consecutive odd integer is x + 2 = 13 + 2 = 15.

Th third consecutive odd integer is x + 4 = 13 + 4 = 17

The fourth consecutive odd integer is x + 6 = 13 + 6 = 19

The 4 consecutive odd integers are {13 ; 15 ; 17 ; 19}.