In 1798 the English scientist Henry Cavendish measured the d
Solution
a)
Getting the mean, X,          
           
 X = Sum(x) / n          
 Summing the items, Sum(x) =    157.99      
 As n =    29      
 Thus,          
 X =    5.447931034   [ANSWER]
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B)
Consider:
Thus, Sum(x - X)^2 =    1.366875862  
       
 Thus, as       
       
 s^2 = Sum(x - X)^2 / (n - 1)      
       
 As n =    29  
       
 s^2 =    0.048816995  
       
 Thus,      
       
 s =    0.220945684   [ANSWER]
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c)
Ordering the data,
4.88
 5.07
 5.1
 5.26
 5.27
 5.29
 5.29
 5.3
 5.34
 5.34
 5.36
 5.39
 5.42
 5.44
 5.46
 5.47
 5.5
 5.53
 5.55
 5.57
 5.58
 5.61
 5.62
 5.63
 5.65
 5.68
 5.75
 5.79
 5.85
Thus, the median is the middle entry, the 15th entry,
Median = 5.46 [ANSWER]
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d)
Here,
u - 3*Sigma = 5.447931034 - 3*0.220945684 = 4.785093982
 u + 3*sigma = 5.447931034 + 3*0.220945684 = 6.110768086
As we can see, there\'s no data beyond these numbers here.
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| x | x - X | (x - X)^2 | |
| 5.5 | 0.052069 | 0.002711 | |
| 5.61 | 0.162069 | 0.026266 | |
| 4.88 | -0.56793 | 0.322546 | |
| 5.07 | -0.37793 | 0.142832 | |
| 5.26 | -0.18793 | 0.035318 | |
| 5.55 | 0.102069 | 0.010418 | |
| 5.36 | -0.08793 | 0.007732 | |
| 5.29 | -0.15793 | 0.024942 | |
| 5.58 | 0.132069 | 0.017442 | |
| 5.65 | 0.202069 | 0.040832 | |
| 5.57 | 0.122069 | 0.014901 | |
| 5.53 | 0.082069 | 0.006735 | |
| 5.62 | 0.172069 | 0.029608 | |
| 5.29 | -0.15793 | 0.024942 | |
| 5.44 | -0.00793 | 6.29E-05 | |
| 5.34 | -0.10793 | 0.011649 | |
| 5.79 | 0.342069 | 0.117011 | |
| 5.1 | -0.34793 | 0.121056 | |
| 5.27 | -0.17793 | 0.031659 | |
| 5.39 | -0.05793 | 0.003356 | |
| 5.42 | -0.02793 | 0.00078 | |
| 5.47 | 0.022069 | 0.000487 | |
| 5.63 | 0.182069 | 0.033149 | |
| 5.34 | -0.10793 | 0.011649 | |
| 5.46 | 0.012069 | 0.000146 | |
| 5.3 | -0.14793 | 0.021884 | |
| 5.75 | 0.302069 | 0.091246 | |
| 5.68 | 0.232069 | 0.053856 | |
| 5.85 | 0.402069 | 0.161659 | 



