PART B Find the direction of the velocity of the canoe relat
/****PART \"B\": Find the direction of the velocity of the canoe relative to the river.
Express your answer as an angle measured south of west. ****/
Solution
vx = vx(canoe, earth) – vx(river, earth)
= 0.520 * cos(315) + 0.570 * cos(180) = -0.202
y component of the velocity
vy= 0.520 * sin(315) + 0.570 * sin(180)
vy(canoe, river) = -0.368
v = sqrt (x2 + y2) = sqrt(-0.2022 + -0.3682)
v = 0.419 m/s
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theta = tan-1( y / x)
= tan-1(-0.368 / -0.202)
= 61.210
